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Luas permukaan balok A
Lp = 2 (p × l) + (p × t) + (l × t)
Lp = 2 (40 × 8) + (40 × 25) + (8 × 25)
Lp = 2 (320 + 1.000 + 200)
Lp = 2 (1.320 + 200)
Lp = 2 (1.520)
Lp = 2 × 1.520
Lp = 3.040 cm²
Luas permukaan balok B
Lp = 2 (p × l) + (p × t) + (l × t)
Lp = 2 (40 × 8) + (40 × 25) + (8 × 30)
Lp = 2 (320 + 1.000 + 240)
Lp = 2 (1.320 + 240)
Lp = 2 (1.560)
Lp = 2 × 1.560
Lp = 3.120 cm²
Selisih
Lp balok A - Lp balok B
= 3.040 - 3.120
= -80 cm²
Luas permukaan A : Luas Permukaan B
2(40x8) + 2(40x25) + 2(8x25) : 2(40×8) + 2(40x30) + 2(8x30)
640 + 2000 + 400 : 640 + 2400 + 480
3.040 cm² : 3.520 cm²
Selisih = 3520 - 3040 = 480 cm²
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