q. - - z
(12 + (2 - (-2))!) + ((34 + (-22))^2) - (2√5 × 2√5) = ...
• Lumayan hard![]()
(12 + (2 - (-2))!) + ((34 + (-22))^2) - (2√5 × 2√5) = ...
• Lumayan hard
= (12 + (2 - (-2)!)) + ((34 + (-22))²) - (2√5 × 2√5)
= (12 + (2 + 2)!) + (33 - 22)²) - (2√5 × 2√5)
= (12 + 4!) = (12 + (4 × 3 × 2 × 1)) = 12 + 24 = 36
= (34 - 22)² = (12)² = 12 × 12 = 144
= (2√5 × 2√5) = √(20 × 20) = √400 = 20
= 36 + 144 - 20
= 180 - 20
= 160
Jawaban:
= (12 + (2 - (-2))!) + ((34 + (-22))^2) - (2√5 × 2√5)
= (12 + 4!) + (12²) - √(20 × 20)
= (12 + (4×3×2×1)) + 144 - √400
= (12 + 24) + 144 - 20
= 36 + 144 - 20
= 180 - 20
= 160
[tex] \tt \#koreksi[/tex]
